Algebraic equations can have 1 solution. They may also have infinitely many solutions, which means that any value of the variable makes the equation true. They may also have no solutions, which means that no value of the variable makes the equation true.

**To better understand how to determine the number of solutions for linear equations …**

## LET’S BREAK IT DOWN!

### Review how to solve an equation.

Emily wants to solve the equation 2*x*-5=11. She knows she needs to do two steps to solve and use inverse operations to isolate the *x*. First, 5 is subtracted on the left side, so add 5 to both sides of the equation. 2*x*-5+5=11+5. This simplifies to 2*x*=16. Next, the *x* is multiplied by 2, so divide both sides by 2. [ggfrac]2x/2[/ggfrac] = [ggfrac]16/2[/ggfrac]. This simplifies to *x*=8. *x* has been isolated, so you know that *x* is equal to 8. Try this yourself: **Solve for x in the equation 3x+5=17.**

### Equations can have one solution.

Emily wants to solve the equation 5*x*-8=3(*x*+4). This equation takes multiple steps to solve and has variables on both sides of the equation! On the right side, the 3 is multiplied by an expression in brackets. To simplify the right side, you need to use the distributive property. Multiply 3 by every term inside the brackets. 3(*x* + 4) = 3(*x*) + 3(4) = 3*x* + 12. Now the equation can be written as 5*x*-8=3*x*+12. Isolate the *x*-terms on one side of the equation (it doesn’t matter which side). Emily decides to put the *x*-terms on the left side, so she focuses on eliminating the -8 first. Add 8 to both sides. 5*x*-8+8=3*x*+12+8, which simplifies to 5*x*=3*x*+20. Next, subtract 3*x* from both sides. 5*x*-3*x*=3*x*+20-3*x*, which simplifies to 2*x*=20. The last step to isolate the *x* is to divide both sides by 2. [ggfrac]2x/2[/ggfrac] = [ggfrac]20/2[/ggfrac]. Then *x* = 10. The equation has one solution, and that solution is 10. Try this yourself: **Solve for x in 8x-12=-4(x+6).**

### Equations can have no solutions.

Adesina is solving 4*x*+8=4*x*+10. There is a variable on both sides of the equal sign, so move the variables to one side and the constants to the other. It doesn’t matter which you do first. First, let's remove the + 8 from the left side by subtracting 8 from both sides. 4*x*+8-8=4*x*+10-8, which simplifies to 4*x*=4*x*+2. Next, remove the 4*x* from the right side by subtracting 4*x* from both sides. 4*x*-4*x*=4*x*+2-4*x*, or 0=2. This equation is not true! It does not matter what value of *x* you choose, you cannot make the left and right sides of the equation equal. This means that the equation has no solutions. Try this yourself: **Show algebraically that 2 x+4=2x+8 has no solutions.**

### Equations can have infinitely many solutions.

Emily is solving 12+3*x*=3*x*+12. Let's start by removing the 12 from the left side. So, subtract 12 from both sides: 12+3*x*-12=3*x*+12-12. When simplified this becomes 3*x*=3*x*. Next, remove the 3*x* from the right side by subtracting 3*x* from both sides. 3*x*-3*x*=3*x*-3*x*, which simplifies to 0=0. This statement is true. It doesn’t matter what value of *x* you choose, the left side is equal to the right side. This means that there are infinitely many solutions. Try this yourself: **Show algebraically that 4+10 x=2(5x+2) has infinitely many solutions.**

## DETERMINING THE NUMBER OF SOLUTIONS FOR LINEAR EQUATIONS VOCABULARY

*a(b+c)=ab+ac*.